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Determine the sum of first 100 terms of given A.P. 12, 14, 16, 18, 20, ...... Activity :- Here, a = 12, d = □, n = 100, S100 = ? Sn = n2[□+(n-1)d] S100 = □2[24+(100-1)d] = 50(24+□) = □ = □ - Algebra

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Sum

Determine the sum of first 100 terms of given A.P. 12, 14, 16, 18, 20, ......

Activity :- Here, a = 12, d = `square`, n = 100, S100 = ?

Sn = `"n"/2 [square + ("n" - 1)"d"]`

S100 = `square/2 [24 + (100 - 1)"d"]`

= `50(24 + square)`

= `square`

= `square`

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Solution

Here, a = 12, d = 14 - 12 = 2, n = 100, S100 = ?

Sn = `"n"/2 [2"a" + ("n" - 1)"d"]`

S100 = `100/2 [24 + (100 - 1)"d"]`

= 50[24 + 99(2)]

= 50(24 + 198)

= 50(222)

11100

Concept: Sum of First n Terms of an AP
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