Sum
Determine the order and degree of the following differential equation:
`("y"''')^2 + 3"y"'' + 3"xy"' + 5"y" = 0`
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Solution
The given D.E. is
`("y"''')^2 + 3"y"'' + 3"xy"' + 5"y" = 0`
This can be written as:
`(("d"^3"y")/"dx"^3)^2 + 3("d"^2"y")/"dx"^2 + "3x"("dy"/"dx") + 5"y" = 0`
This D.E. has highest order derivative `("d"^3"y")/"dx"^3` with power 2.
∴ the given D.E. has order 3 and degree 2.
Is there an error in this question or solution?
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