Determine the least number which when divided by 3, 4 and 5 leaves remainder 2 in each case. - Mathematics

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Sum

Determine the least number which when divided by 3, 4 and 5 leaves remainder 2 in each case.

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Solution

We have,

 2 
 3, 4, 5
 2
 3, 2, 5
 3
 3, 1, 5
 5
 1, 1, 5
 
 1, 1, 1

Since, the LCM of 3, 4 and 5 is 2 × 2 × 3 × 5 = 60.

∴ The required number is 6 is the least number which when divided by 3, 4 and 5 leaves remainder 2 in each case.

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Chapter 1: Number System - Exercise [Page 19]

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NCERT Exemplar Class 6 Mathematics
Chapter 1 Number System
Exercise | Q 189 | Page 19

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