# Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated. - Chemistry

Sum

Determine the osmotic pressure of a solution prepared by dissolving 2.5 × 10−2 g of K2SO4 in 2L of water at 25°C, assuming that it is completely dissociated.

(R = 0.0821 L atm K−1 mol−1, Molar mass of K2SO4 = 174 g mol−1)

#### Solution

When K2SO4 is dissolved in water , ions are produced.

Total number of ions produced = 3

i = 3

pi = "iCRT" = ("i"xx"n"xx"R"xx"T")/"V"

=> pi = 3 xx (2.5 xx 10^-2 "g")/(174 "g mol"^-1) xx (0.0821 "L"  "atm"  "K"^-1 "mol"^-1)/"2L" xx 298 "K"

= 5.27 xx 10^-3 "atm"

Concept: Colligative Properties and Determination of Molar Mass - Osmosis and Osmotic Pressure
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