# Determine the Order and Degree (If Defined) of the Following Differential Equation:- ( D S D T ) 4 + 3 S D 2 S D T 2 = 0 - Mathematics

Short Note
Sum

Determine the order and degree (if defined) of the following differential equation:-

$\left( \frac{ds}{dt} \right)^4 + 3s\frac{d^2 s}{d t^2} = 0$

#### Solution

$\left( \frac{ds}{dt} \right)^4 + 3s\frac{d^2 s}{d t^2} = 0$

The highest order derivative in the given equation is $\frac{d^2 s}{d t^2}$ and its power is 1.

Therefore, the given differential equation is of second order and first degree.
i.e., Order = 2 and degree = 1

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#### APPEARS IN

RD Sharma Class 12 Maths
Chapter 22 Differential Equations
Revision Exercise | Q 1.1 | Page 144