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Determine Order and Degree(If Defined) of Differential Equation `((Ds)/(Dt))^4 + 3s (D^2s)/(Dt^2) = 0` - CBSE (Commerce) Class 12 - Mathematics

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Question

Determine order and degree(if defined) of differential equation `((ds)/(dt))^4 + 3s  (d^2s)/(dt^2) = 0`

Solution

`((ds)/(dt))^4 + 3s  (d^2s)/(dt^2) = 0`

The highest order derivative present in the given differential equation is (d^2s)/(dt)^2` . Therefore, 

It is a polynomial equation in `(d^2s)/(dt^2)and (ds)/(dt)`. The power raised to (d^2s)/(dt^2) is 1

Hence, its degree is one.

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APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 12 (2018 to Current)
Chapter 9: Differential Equations
Q: 3 | Page no. 382
Solution Determine Order and Degree(If Defined) of Differential Equation `((Ds)/(Dt))^4 + 3s (D^2s)/(Dt^2) = 0` Concept: Order and Degree of a Differential Equation.
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