# Determine the Nature of the Roots of the Following Quadratic Equation: 3x^2-2sqrt6x+2=0 - Mathematics

Determine the nature of the roots of the following quadratic equation:

3x^2-2sqrt6x+2=0

#### Solution

The given quadric equation is 3x^2-2sqrt6x+2=0

Here, a = 3, b=-2sqrt6 and c = 2

As we know that D = b2 - 4ac

Putting the value of a = 3, b=-2sqrt6 and c = 2

D = (-2sqrt6)^2-4xx3xx2

= 24 - 24

= 0

Since, D = 0

Therefore, root of the given equation are real and equal.

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#### APPEARS IN

RD Sharma Class 10 Maths
Exercise 4.6 | Q 1.5 | Page 41