Advertisement Remove all ads

Determine the Empirical Formula of the Compound Whose Composition by Mass is 42% Nitrogen, 48% Oxygen and 9% Hydrogen. - Chemistry

Short Note

Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]

Advertisement Remove all ads

Solution

Element Atomic mass Percentage Relative number of moles  Simplest mole ratio Whole number ratio
N 14 42 42/14 = 3 3/3 = 1 1
O 16 48 48/16 = 3 3/3 = 1 1
H 1 9 9/1 = 9 9/3 = 3 3

So the empirical formula of the compound is NH2OH.

Concept: Deduction of Simple (Empirical) and Molecular Formula from the Percentage Composition of a Compound
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Frank ICSE Class 10 Chemistry Part 2
Chapter 5 Mole Concept And Stoichiometry
Exercise | Q 6 | Page 118
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×