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# Determine the Empirical Formula of the Compound Whose Composition by Mass is 42% Nitrogen, 48% Oxygen and 9% Hydrogen. - Chemistry

Short Note

Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]

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#### Solution

 Element Atomic mass Percentage Relative number of moles Simplest mole ratio Whole number ratio N 14 42 42/14 = 3 3/3 = 1 1 O 16 48 48/16 = 3 3/3 = 1 1 H 1 9 9/1 = 9 9/3 = 3 3

So the empirical formula of the compound is NH2OH.

Concept: Deduction of Simple (Empirical) and Molecular Formula from the Percentage Composition of a Compound
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#### APPEARS IN

Frank ICSE Class 10 Chemistry Part 2
Chapter 5 Mole Concept And Stoichiometry
Exercise | Q 6 | Page 118
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