Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]
|Element||Atomic mass||Percentage||Relative number of moles||Simplest mole ratio||Whole number ratio|
|N||14||42||42/14 = 3||3/3 = 1||1|
|O||16||48||48/16 = 3||3/3 = 1||1|
|H||1||9||9/1 = 9||9/3 = 3||3|
So the empirical formula of the compound is NH2OH.
Concept: Deduction of Simple (Empirical) and Molecular Formula from the Percentage Composition of a Compound
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