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Determine the A.P. whose third term is 16 and the 7th term exceeds the 5th term by 12. - Mathematics

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Determine the A.P. whose third term is 16 and the 7th term exceeds the 5th term by 12.

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Solution

=a3 = 16

a + (3 − 1) d = 16

a + 2d = 16 (1)

a7 − a5 = 12

[a+ (7 − 1) d] − [a + (5 − 1) d]= 12

(a + 6d) − (a + 4d) = 12

2d = 12

d = 6

From equation (1), we obtain

a + 2 (6) = 16

a + 12 = 16

a = 4

Therefore, A.P. will be

4, 10, 16, 22, …

Concept: nth Term of an AP
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APPEARS IN

NCERT Class 10 Maths
Chapter 5 Arithmetic Progressions
Exercise 5.2 | Q 16 | Page 106
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