Advertisement Remove all ads

Derive an Expression for the Electric Potential at Any Point Along the Axial Line of an Electric Dipole. - Physics

Question

Derivation
Sum

Derive an expression for the electric potential at any point along the axial line of an electric dipole.

Solution

Suppose P is a point on the axial position of the dipole.
Length of dipole = 2a  
Suppose point P is at the distance 'r' from the center of the dipole. 

The potential at a point is V = `1/(4piε_0).Q/r`

So, the potential at P due to q is V= `1/(4piε_0).q/(a+r)`

Potential at P due to -q is V-q = `1/(4piε_0).(-q)/(a-r)`

The total potential at P is `V = V_q + V_(-q)`

= `1/(4piε_0).q/((a + r)) + 1/(4piε_0).(-q)/((r - a))`

= `q/(4piε_0)[1/((a + r)) + 1/((a - r))]`

V = `q/(4piε_0).(2a)/((a^2 - r^2))`

Concept: Potential Due to an Electric Dipole
  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications
Login
Create free account


      Forgot password?
View in app×