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# Find Dy/Dx for Y = Sec^(-1) (1/(2x^2 - 1)), 0 < X < 1/Sqrt2 - CBSE (Science) Class 12 - Mathematics

ConceptDerivatives of Inverse Trigonometric Functions

#### Question

Find dy/dx

y = sec^(-1) (1/(2x^2 - 1)), 0 < x < 1/sqrt2

#### Solution

The given relationship is y = sec^(-1) (1/(2x^2 - 1))

Differentiating this relationship with respect to x, we obtain

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#### APPEARS IN

NCERT Solution for Mathematics Textbook for Class 12 (2018 to Current)
Chapter 5: Continuity and Differentiability
Q: 15 | Page no. 169

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Solution Find Dy/Dx for Y = Sec^(-1) (1/(2x^2 - 1)), 0 < X < 1/Sqrt2 Concept: Derivatives of Inverse Trigonometric Functions.
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