#### Question

If y=e^{ax },show that `xdy/dx=ylogy`

#### Solution

`y=e^(ax)`

`y=e^(ax) ...............(i)`

`logy=ax..............(ii)`

`dy/dx=ae^(ax)`

`dy/dx=ay`

`xdy/dx=axy `

`xdy/dx=ylogy `

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#### APPEARS IN

Solution If y=e^(ax) ,show that x dy/dx=y logy Concept: Derivatives of Implicit Functions.