#### Question

The area of the upper face of a rectangular block is 0.5 m by 0.5 m and the lower face is fixed. The height of the block is 1 cm. A shearing force applied at the top face produces a displacement of 0.015 mm. Find the strain and shearing force.

(Modulus of rigidity: η = 4.5 x 10^{10} N/m^{2})

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Solution for question: The Area of the Upper Face of a Rectangular Block is 0.5 M ' 0.5 M and the Lower Face is Fixed. the Height of the Block is 1 Cm. a Shearing Force Applied at the Top Face Produces a Displacement of 0.015 Mm. Find the Strain and Shearing Force. concept: Definition of Stress and Strain. For the courses HSC Science (Computer Science), HSC Science (Electronics), HSC Science (General)