Answer 1

Given: λ = 0.017 h^-1

To find: t_1/2

Formula: `"t"_(1//2) = 0.693/lambda`

Calculation: `"t"_(1//2) = 0.693/lambda`

`= 0.693/(0.017 "h"^(-1))` = 40.77 h (by using log table)

Thus, the half-life of ¹⁹⁷Hg is 40.77 h.