Maharashtra State BoardHSC Science (General) 11th
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Decay constant of 197Hg is 0.017 h-1. What is its half-life? - Chemistry

Numerical

Decay constant of 197Hg is 0.017 h-1. What is its half-life?

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Solution

Given: λ = 0.017 h-1

To find: t1/2

Formula: `"t"_(1//2) = 0.693/lambda`

Calculation: `"t"_(1//2) = 0.693/lambda`

`= 0.693/(0.017 "h"^(-1))` = 40.77 h (by using log table)

Thus, the half-life of 197Hg is 40.77 h.

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Balbharati Chemistry 11th Standard Maharashtra State Board
Chapter 13 Nuclear Chemistry and Radioactivity
Exercises | Q 3. (L) | Page 202
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