Numerical

Decay constant of ^{197}Hg is 0.017 h^{-1}. What is its half-life?

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#### Solution

**Given:** λ = 0.017 h^{-1}

**To find:** t_{1/2}

**Formula: **`"t"_(1//2) = 0.693/lambda`

**Calculation: **`"t"_(1//2) = 0.693/lambda`

`= 0.693/(0.017 "h"^(-1))` = 40.77 h (by using log table)

Thus, the half-life of ^{197}Hg is **40.77 h**.

Concept: Radioactive Decays

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