# ∫ D X √ 2 a X − X 2 = a N Sin − 1 [ X a − 1 ] the Value of N is You May Use Dimensional Analysis to Solve the Problem. - Physics

MCQ

$\int\frac{dx}{\sqrt{2ax - x^2}} = a^n \sin^{- 1} \left[ \frac{x}{a} - 1 \right]$
The value of n is

#### Options

• 0

• -1

• 1

• none of these.

#### Solution

0
[ax] = [x2]
⇒ [a] = [x]    ...(1)
Dimension of LHS = Dimension of RHS

$\Rightarrow \left[ \frac{dx}{\sqrt{x^2}} \right] = \left[ a^n \right]$

$\Rightarrow \left[ \frac{L}{L} \right] = \left[ a^n \right] . . . (2)$

$[ L^0 ] = [ a^n ]$

$n = 0$

#### Notes

You may use dimensional analysis to solve the problem.

Concept: What is Physics?
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#### APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 1
Chapter 1 Introduction to Physics
MCQ | Q 6 | Page 9
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