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In the Given Figure, Ab is the Diameter of a Circle with Centre O. ∠Bcd = 130°. Find: (I) ∠Dab (Ii) ∠Dba - Mathematics

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Question

In the given figure, AB is the diameter of a circle with centre O. ∠BCD = 130°. Find:
(i) ∠DAB
(ii) ∠DBA

Solution

i. ABCD is a cyclic quadrilateral
m∠DAB = 180° − ∠DCB
= 180° - 130°
= 50°

ii. In ∆ADB,
m∠DAB + m∠ADB + m∠DBA = 180°
⇒ 50° + 90° + m∠DBA = 180°
⇒ m∠DBA = 40°

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APPEARS IN

 Selina Solution for Concise Mathematics for Class 10 ICSE (2020 (Latest))
Chapter 17: Circles
Exercise 17(A) | Q: 49 | Page no. 262
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In the Given Figure, Ab is the Diameter of a Circle with Centre O. ∠Bcd = 130°. Find: (I) ∠Dab (Ii) ∠Dba Concept: Cyclic Properties.
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