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In the Given Figure, Ab is the Diameter of a Circle with Centre O. ∠Bcd = 130°. Find: (I) ∠Dab (Ii) ∠Dba - ICSE Class 10 - Mathematics

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Question

In the given figure, AB is the diameter of a circle with centre O. ∠BCD = 130°. Find:
(i) ∠DAB
(ii) ∠DBA

Solution

i. ABCD is a cyclic quadrilateral
m∠DAB = 180° − ∠DCB
= 180° - 130°
= 50°

ii. In ∆ADB,
m∠DAB + m∠ADB + m∠DBA = 180°
⇒ 50° + 90° + m∠DBA = 180°
⇒ m∠DBA = 40°

  Is there an error in this question or solution?
Solution In the Given Figure, Ab is the Diameter of a Circle with Centre O. ∠Bcd = 130°. Find: (I) ∠Dab (Ii) ∠Dba Concept: Cyclic Properties.
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