#### Question

ABCD is a cyclic quadrilateral in a circle with centre O. If ∠ADC = 130°; find ∠ BAC.

#### Solution

Here ∠ACB = 90°

(Angle in a semicircle is right angle)

Also, ∠ABC = 180° -∠ADC = 180° - 130° = 50°

(pair of opposite angles in a cy clic quadrilateral are supplementary)

By angle sum property of right triangle ACB,

∠BAC = 90° - ∠ABC = 90° - 50° = 40°

Is there an error in this question or solution?

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Abcd is a Cyclic Quadrilateral in a Circle with Centre O. If ∠Adc = 130°; Find ∠ Bac. Concept: Cyclic Properties.

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