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In the following figure, if ΔABE ≅ ΔACD, show that ΔADE ∼ ΔABC. - CBSE Class 10 - Mathematics

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Question

In the following figure, if ΔABE ≅ ΔACD, show that ΔADE ∼ ΔABC.

Solution

It is given that ΔABE ≅ ΔACD.

∴ AB = AC [By CPCT] (1)

And, AD = AE [By CPCT] (2)

In ΔADE and ΔABC,

`(AD)/(AB) = (AE)/(AC) `  [Dividing equation 2 by 1]

A = ∠A [Common angle]

∴ ΔADE ∼ ΔABC [By SAS similarity criterion]

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 10 (2019 to Current)
Chapter 6: Triangles
Ex. 6.30 | Q: 6 | Page no. 140
Solution In the following figure, if ΔABE ≅ ΔACD, show that ΔADE ∼ ΔABC. Concept: Criteria for Similarity of Triangles.
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