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In the following figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that - CBSE Class 10 - Mathematics

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Question

In the following figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that:

ΔPDC ∼ ΔBEC

Solution

In ΔPDC and ΔBEC,

∠PDC = ∠BEC (Each 90°)

∠PCD = ∠BCE (Common angle)

Hence, by using AA similarity criterion,

ΔPDC ∼ ΔBEC

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 10 (2019 to Current)
Chapter 6: Triangles
Ex. 6.30 | Q: 7.4 | Page no. 140
Solution In the following figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that Concept: Criteria for Similarity of Triangles.
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