#### Question

D is a point on the side BC of ∆ABC such that ∠ADC = ∠BAC. Prove that ` \frac{CA}{CD}=\frac{CB}{CA} or, CA^2 = CB × CD.`

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Solution for question: D is a point on the side BC of ∆ABC such that ∠ADC = ∠BAC. Prove that CA/CD=CB/CAor, CA^2 = CB × CD. concept: Criteria for Similarity of Triangles. For the course CBSE