#### Question

In Fig. 10.92, it is given that AB = CD and AD = BC. Prove that ΔADC ≅ ΔCBA.

#### Solution

Given that in the figure AB =CD and . AD=BC

We have to prove

ΔADC≅ΔCBA

Now,

Consider ΔADC and ΔCBA

We have

AB = CD [Given]

BC = AD [Given]

And AC=AC [Common side]

So, by SSS congruence criterion, we have

ΔADC≅ΔCBA

∴ Hence proved

Is there an error in this question or solution?

Solution In Fig. 10.92, It is Given that Ab = Cd and Ad = Bc. Prove that δAdc ≅ δCba. Concept: Criteria for Congruence of Triangles.