ABCD is a square, X and Yare points on sides AD and BC respectively such that AY = BX. Prove that BY = AX and ∠BAY = ∠4BX.
Given that ABCD is a square, X and Y are points on sides AD and BC respectively such that AY = BX.
We have to prove BY = AX and ∠BAY = ∠ABX
Join B and X, A and Y.
Since, ABCD is a square ⇒ ∠ DAB = ∠CBA =90°
⇒ ∠XAB= ∠YBA=90° .............(1)
Now, consider triangle XAB and YBA
∠XAB=∠YBA=90° ...........[From (1)]
And AB=BA [Common side]
So, by RHS congruence criterion, we have ΔXAB≅ΔYBA
Now, we know that corresponding parts of congruent triangles are equal.
∴ BY=AX and ∠BAY=∠ABX
∴ Hence proved