∫cos2xsin2x dx - Mathematics and Statistics

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Sum

`int (cos2x)/(sin^2x)  "d"x`

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Solution

`int (cos2x)/(sin^2x)  "d"x`

= `int (1 - 2sin^2x)/(sin^2x)  "d"x`     ......[∵ cos 2θ = 1 − 2sin2θ]

= `int(1/(sin^2x) - (2sin^2x)/(sin^2x))  "d"x`

= `int ("cosec"^2x - 2)  "d"x`

= −cot x − 2x + c

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Chapter 2.3: Indefinite Integration - Very Short Answers

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