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# Corresponding Sides of Two Similar Triangles Are in the Ratio 1 : 3. If the Area of the Smaller Triangle in 40 Cm2, Find the Area of the Larger Triangle. - Mathematics

Sum

Corresponding sides of two similar triangles are in the ratio 1 : 3. If the area of the smaller triangle in 40 cm2, find the area of the larger triangle.

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#### Solution

Since the ratio of areas of two similar triangles is equal to the ratio of the squares of any two corresponding sides.

\text{(Area of smaller triangle)}/\text{(Area of larger  triangle)}=\text{(Corresponding side of smaller triangle)}^2/\text{(Corresponding side of larger triangle)}^2

\text{(Area of smaller triangle)}/\text{(Area of larger  triangle)}1^2/3^2

40/\text{(Area of larger  triangle)}1/9

Area of larger  triangle = (40xx9)/(1) = 360 cm^2

Hence the area of the larger triangle is  360 cm^2

Concept: Triangles Examples and Solutions
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#### APPEARS IN

RD Sharma Class 10 Maths
Chapter 7 Triangles
Q 19 | Page 126
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