HSC Commerce (Marketing and Salesmanship) 12th Board ExamMaharashtra State Board
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# Solution for If 'f' is continuous at x = 0, then find f(0). f(x)=(15x-3x-5x+1)/(xtanx) , x!=0 - HSC Commerce (Marketing and Salesmanship) 12th Board Exam - Mathematics and Statistics

#### Question

If 'f' is continuous at x = 0, then find f(0).

f(x)=(15^x-3^x-5^x+1)/(xtanx) , x!=0

#### Solution

f(x)=(15^x-3^x-5^x+1)/(xtanx) , x!=0

lim_(x->0)f(x)=lim_(x->0)(15^x-3^x-5^x+1)/(xtanx)

=lim_(x->0)(3^x(5^x-1)-(5^x-1))/(xtanx)

=lim_(x->0)((3^x-1)(5^x-1))/(xtanx)

=lim_(x->0)([(5^x-1)/x][(3^x-1)/x])/ ((xtanx/x^2))

=(log5.log3)/1

=log5.log3

As function is continuous at x=0

f(0)=lim_(x->0)f(x)

f(0)=log5.log3

Is there an error in this question or solution?

#### APPEARS IN

2014-2015 (March) (with solutions)
Question 3.1.2 | 3 marks

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Solution for question: If 'f' is continuous at x = 0, then find f(0). f(x)=(15x-3x-5x+1)/(xtanx) , x!=0 concept: Continuous Function of Point. For the courses HSC Commerce (Marketing and Salesmanship), HSC Commerce
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