Construct ΔABC, given m∠A = 60°, m∠B = 30° and AB = 5.8 cm.

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#### Solution

A rough sketch of the required ΔABC is as follows.

The steps of construction are as follows.

1) Draw a line segment AB of length 5.8 cm.

2) At point A, draw a ray AX making 60º angle with AB.

3)At point B, draw a ray BY, making 30º angle with AB.

4) Point C has to lie on both the rays, AX and BY. Therefore, C is the point of intersection of these two rays.

This is the required triangle ABC.

Is there an error in this question or solution?

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