Construct a triangle ABC in which BC = 8 cm, ∠B = 45° and AB − AC = 3.5 cm.
The below given steps will be followed to draw the required triangle.
Step I:- Draw the line segment BC = 8 cm and at point B, make an angle of 45°, say ∠XBC.
Step II:- Cut the line segment BD = 3.5 cm (equal to AB − AC) on ray BX.
Step III:- Join DC and draw the perpendicular bisector PQ of DC.
Step IV:- Let it intersect BX at point A. Join AC. ΔABC is the required triangle.
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