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Construct a triangle ABC with BC = 7 cm, ∠B = 60° and AB = 6 cm. Construct another triangle whose sides are `3/4` times the corresponding sides of ∆ABC.

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#### Solution

Given: A ∆ABC with BC=7 cm, ∠B=60° and AB=6 cm

__Steps of Construction__

1. Draw a line segment AB = 6 cm.

2. With B as centre, draw ∠B=60°.

3. With B as centre and radius BC = 7 cm, draw an arc.

4. Join AC to obtain ∆ABC.

5. Below AB*, *make an acute angle ∠BAX.

6. Along AX*,* mark off four points A_{1}, A_{2}, A_{3} and A_{4} such that AA_{1}=A_{1}A_{2}=A_{2}A_{3}=A_{3}A_{4}

7. Join A_{4}B

8. From A_{3}, draw A_{3}B'∥A_{4}B*.*

9. From B', draw B'C'∥BC.

Thus, ∆AB'C' is the required triangle with each of its side `3/4` times the size of the corresponding sides of ∆ABC*.*

Concept: Division of a Line Segment

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