Chart
Construct the truth table of the following statement pattern.
(p ∧ ∼q) ↔ (p → q)
Advertisement Remove all ads
Solution
| p | q | ∼ q | p ∧ ∼ q | p → q | (p ∧ ∼ q) ↔ (p → q) |
| T | T | F | F | T | F |
| T | F | T | T | F | F |
| F | T | F | F | T | F |
| F | F | T | F | T | F |
Concept: Logical Connective, Simple and Compound Statements
Is there an error in this question or solution?
APPEARS IN
Advertisement Remove all ads
