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Sum
Construct the truth table for the following statement pattern.
(p ∧ ~q) ↔ (q → p)
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Solution
p | q | ~q | p∧~q | q→p | (p∧~q)↔(q→p) |
T | T | F | F | T | F |
T | F | T | T | T | T |
F | T | F | F | F | T |
F | F | T | F | T | F |
Is there an error in this question or solution?