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Construct a Quadrilateral Abcd, Where ∠A = 65°, ∠B = 105°, ∠C = 75° Bc = 5.7 Cm and Cd = 6.8 Cm. - Mathematics

Course
ConceptConstructing a Quadrilateral When Two Adjacent Sides and Three Angles Are Known

Question

Construct a quadrilateral ABCD, where ∠A = 65°, ∠B = 105°, ∠C = 75° BC = 5.7 cm and CD = 6.8 cm.

Solution

$\text { We know that the sum of all the angles in a quadrilateral is 360 } .$

$\text { i . e} . , \angle A + \angle B + \angle C + \angle D = 360^\circ$

$\Rightarrow \angle D = 115^\circ$

Steps of Construction:

Step I: Draw BC = 5 . 7 cm .

$\text { Step II: Construct } \angle XBC = 105^\circ\text { at B and } \angle BCY = 105^\circ at C .$

Step III : With C as the centre and radius 6 . 8 cm, cut off CD = 6 . 8 cm .

$\text { Step IV: At D, draw } \angle CDZ = 115^\circ \text { such that it meets BY at A } .$

The quadrilateral so obtained is the required quadrilateral .

Is there an error in this question or solution?

APPEARS IN

RD Sharma Solution for Mathematics for Class 8 by R D Sharma (2019-2020 Session) (2017 to Current)
Chapter 18: Practical Geometry (Constructions)
Ex. 18.5 | Q: 5 | Page no. 13
Solution Construct a Quadrilateral Abcd, Where ∠A = 65°, ∠B = 105°, ∠C = 75° Bc = 5.7 Cm and Cd = 6.8 Cm. Concept: Constructing a Quadrilateral - When Two Adjacent Sides and Three Angles Are Known.
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