Construct Δ ABC, in which BC =5.2 cm, ∠ ACB = 45 ° and perimeter of Δ ABC is 10 cm.
Perimeter of △ABC = 10 cm
⇒ AB + BC + AC = 10 cm
⇒ AB + 5.2 + AC = 10 cm
⇒ AB + AC = 4.8 cm
A triangle can be only possible if the sum of the sides of a traingle is greater than the third side.
But here, AB + AC < BC
Hence, the construction of △ABC is not possible.