Construct a δAbc in Which Bc = 3.4 Cm, Ab − Ac = 1.5 Cm and ∠B = 45°. - Mathematics

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Construct a ΔABC in which BC = 3.4 cm, AB − AC = 1.5 cm and ∠B = 45°.

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Steps of construction:
Step 1: Draw a line segment BC of 3.5cm
Step 2: At B, draw an angle XBC of 45°
Step 3: With center B and radius 1.5cm, draw an arc which intersects BX at D.
Step 4: Join DC
Step 5: Draw the perpendicular bisector of DC which intersects BD produced at A.
Step 6: Join AC
∴ΔABC is the required triangle.

Concept: Some Constructions of Triangles
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RD Sharma Mathematics for Class 9
Chapter 16 Constructions
Exercise 16.3 | Q 3 | Page 18

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