Question

Construct a ΔABC in which AB + AC = 5.6 cm, BC = 4.5 cm, AB − AC = 1.5 cm and ∠B = 45°.

Answer 1

Steps of construction:
Step 1: Draw a line segment BC of 4.5cm 
Step 2: At B, draw an angle XBC of 45°
Step 3: With center B and radius 5 6 , cm  draw an arc which intersects BX at D.
Step 4: Join DC
Step 5: Draw the perpendicular bisector of DC which intersects BD at A.
Step 6: Join AC
∴ΔABC is a required triangle