Maharashtra State BoardSSC (English Medium) 9th Standard
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Construct δ Abc, Such that Bc = 6 Cm, ∠ Abc = 100 ∘ and Ac − Ab = 2.5cm. - Geometry

Diagram

Construct Δ ABC, such that BC = 6 cm, ∠ABC = 100°   and  AC - AB = 2.5cm.

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Solution

​Steps of construction: 
(1) Draw seg BC of length 6 cm.
(2) Draw ray BE such that ∠CBE = 100°
(3) Take point D on the opposite of ray BE such that BD = 2.5 cm.
(4) Construct perpendicular bisector of seg DC.
(5) Name the point of intersection of ray BE and the perpendicular bisector of DC as A.
(6) Draw seg AC. 
Therefore, △ABC is required triangle.

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APPEARS IN

Balbharati Mathematics 2 Geometry 9th Standard Maharashtra State Board
Chapter 4 Constructions of Triangles
Practice Set 4.2 | Q 3 | Page 54
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