Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10th
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Construct a triangle similar to a given triangle PQR with its sides equal to 23 of the corresponding sides of the triangle PQR (scale factor 23<1) - Mathematics

Sum

Construct a triangle similar to a given triangle PQR with its sides equal to `2/3` of the corresponding sides of the triangle PQR (scale factor `2/3 < 1`)

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Solution

Given ∆PQR, we are required to construct another triangle whose sides are `2/3` of the corresponding sides of the ∆PQR

Steps of construction:

(i) Construct a ∆PQR with any measurement.

(ii) Draw a ray QX making an acute angle with QR on the side opposite to the vertex P.

(iii) Locate 3 points Q1, Q2 and Q3 on QX.

So that QQ1 = Q1Q2 = Q2Q3

(iv) Join Q3 R and draw a line through Q2 parallel to Q3 R to intersect QR at R’.

(v) Draw a line through R’ parallel to the line RP to intersect QP at P’. Then ∆P’QR’ is the required triangle.

Concept: Similarity
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APPEARS IN

Samacheer Kalvi Mathematics Class 10 SSLC Tamil Nadu State Board
Chapter 4 Geometry
Exercise 4.1 | Q 10 | Page 171
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