Construct a parallelogram ABCD, if :
BC = 4.5 cm, CD = 5.2 cm and ∠ADC = 75°.
The rough figure is as follow :
∵ opposite sides of ||gm are equal
∴ AD = BC = 4.5 cm.
∴ Actual construction is as follow:
- Draw CD = 5.2 cm.
- Draw ZCDP = 75°
- Cut DA = 4.5 cm.
- A drawn arc of radius 5.2 cm.
- From C, draw an arc of radius 4.5 cm which meets the first arc at B.
- Join AB and CB.
Thus ABCD is the required ||gm.
Concept: Construction of Parallelograms
Is there an error in this question or solution?