Considering the Case of a Parallel Plate Capacitor Being Charged, Show How One is Required to Generalize Ampere'S Circuital Law to Include the Term Due to Displacement Current. - Physics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads

Considering the case of a parallel plate capacitor being charged, show how one is required to generalize Ampere's circuital law to include the term due to displacement current.

Advertisement Remove all ads


Using Gauss’ law, the electric flux ΦE of a parallel plate capacitor having an area A, and a total charge Q is



Where electric field is


As the charge Q on the capacitor plates changes with time, so current is given by

i = dQ/dt



This is the missing term in Ampere’s circuital law.

So the total current through the conductor is

i = Conduction current (ic) + Displacement current (id)


As Ampere’s circuital law is given by


After modification we have Ampere−Maxwell law is given as


The total current passing through any surface, of which the closed loop is the perimeter, is the sum of the conduction and displacement current.

Concept: The Parallel Plate Capacitor
  Is there an error in this question or solution?
2013-2014 (March) All India Set 2

      Forgot password?
View in app×