# Consider the D−T reaction (deuterium−tritium fusion) X12X2122H+X13X2123H⟶X24X2224He+n Calculate the energy released in MeV in this reaction from the data: mHm(12H)= 2.014102 u mHm(13H)= 3.016049 u - Physics

Numerical

Consider the D−T reaction (deuterium−tritium fusion)

$\ce{^2_1H + ^3_1H -> ^4_2He + n}$

Calculate the energy released in MeV in this reaction from the data:

"m"(""_1^2"H")= 2.014102 u

"m"(""_1^3"H")= 3.016049 u

#### Solution

Take the D-T nuclear reaction:  $\ce{^2_1H + ^3_1H -> ^4_2He + n}$

It is given that:

Mass of ""_1^2"H" m1= 2.014102 u

Mass of ""_1^3"H" m= 3.016049 u

Mass of ""_2^4"He" m= 4.002603 u

Mass of ""_0^1"n" m= 1.008665 u

Q-value of the given D-T reaction is:

Q = [m+ m2 − m3 − m4] c2

= [2.014102 + 3.016049 − 4.002603 − 1.008665] c2

= [0.018883 c2] u

But 1 u = 931.5 MeV/c2

∴Q = 0.018883 × 931.5 = 17.59 MeV

Is there an error in this question or solution?

#### APPEARS IN

NCERT Physics Part 1 and 2 Class 12
Chapter 13 Nuclei
Exercise | Q 13.28 (a) | Page 465
NCERT Class 12 Physics Textbook
Chapter 13 Nuclei
Exercise | Q 28.1 | Page 465
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