Consider the D−T reaction (deuterium−tritium fusion) X12X2122H+X13X2123H⟶X24X2224He+n Calculate the energy released in MeV in this reaction from the data: mHm(12H)= 2.014102 u mHm(13H)= 3.016049 u - Physics

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Numerical

Consider the D−T reaction (deuterium−tritium fusion)

\[\ce{^2_1H + ^3_1H -> ^4_2He + n}\]

Calculate the energy released in MeV in this reaction from the data:

`"m"(""_1^2"H")`= 2.014102 u

`"m"(""_1^3"H")`= 3.016049 u

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Solution

Take the D-T nuclear reaction:  \[\ce{^2_1H + ^3_1H -> ^4_2He + n}\]

It is given that:

Mass of `""_1^2"H"` m1= 2.014102 u

Mass of `""_1^3"H"` m= 3.016049 u

Mass of `""_2^4"He"` m= 4.002603 u

Mass of `""_0^1"n"` m= 1.008665 u

Q-value of the given D-T reaction is:

Q = [m+ m2 − m3 − m4] c2

= [2.014102 + 3.016049 − 4.002603 − 1.008665] c2

= [0.018883 c2] u

But 1 u = 931.5 MeV/c2

∴Q = 0.018883 × 931.5 = 17.59 MeV

Concept: Radioactivity - Beta Decay
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Chapter 13: Nuclei - Exercise [Page 465]

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NCERT Physics Class 12
Chapter 13 Nuclei
Exercise | Q 13.28 (a) | Page 465
NCERT Physics Class 12
Chapter 13 Nuclei
Exercise | Q 28.1 | Page 465

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