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Consider the Situation Shown in the Following Figure. Both the Pulleys and the String Are Light and All the Surfaces Are Frictionless. (A) Find the Acceleration - Physics

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Sum

Consider the situation shown in the following figure. Both the pulleys and the string are light and all the surfaces are frictionless. (a) Find the acceleration of the mass M; (b) find the tension in the string; (c) calculate the force exerted by the clamp on the pulley A in the figure.

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Solution

Let the acceleration of mass M be a.
So, the acceleration of mass 2M will be \[\frac{a}{2}\]

(a) 2M(a/2) − 2T = 0
⇒ Ma = 2T
T + Ma − Mg = 0
\[\Rightarrow \frac{Ma}{2} + Ma = Mg \]
\[ \Rightarrow 3Ma = 2Mg\]
\[ \Rightarrow a = \frac{2g}{3}\]

(b) Tension,
\[T = \frac{Ma}{2} = \frac{M}{2} \times \frac{2g}{3} = \frac{Mg}{3}\] 

(c) Let T' = resultant of tensions

\[\therefore T' = \sqrt{T^2 + T^2} = \sqrt{2}T\]

\[ \therefore T' = \sqrt{2}T = \frac{\sqrt{2}Mg}{3}\]

\[\text{Again, }\tan\theta = \frac{T}{T} = 1\]

\[ \Rightarrow \theta = 45^\circ\]

So, the force exerted by the clamp on the pulley is `(sqrt2"Mg")/3` at an angle of 45° with the horizontal.

Concept: Newton’s Second Law of Motion
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APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 1
Chapter 5 Newton's Laws of Motion
Q 31 | Page 81
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