Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12
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# Consider the Situation of the Previous Problem. Find the Average Electric Field Energy Stored in the Capacitor and the Average Magnetic Field Energy Stored in the Coil. - Physics

Sum

Consider the situation of the previous problem. Find the average electric field energy stored in the capacitor and the average magnetic field energy stored in the coil.

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#### Solution

Given:
Resistance in the LCR circuit, R = 300 Ω
Capacitance in the LCR circuit, C = 20 μF = 20 × 10−6 F
Inductance in the LCR circuit, L = 1 henry
Net impedance of the LCR circuit, = 500 ohm
RMS value of voltage,  = 50 V
RMS value of current, Irms = 0.1 A
Peak current (I0) is given by,
I_0 = (E_rms sqrt2) /Z = (50xx 1.4xx414)/(500) = 01414 A
Electrical energy stored in capacitor  is given by,
U_C = 1/2 CV^2
rArr U_C = 1/2 xx 20xx10^-6xx50xx50
rArr U_C = 25xx10^-3 J =25 mJ
Magnetic field energy stored in the coil (UL) is given by,
U_L = 1/2 LI_0^2
rArr U_L = 1/2xx1xx(0.1414)^2
rArr U_L ≈ 5xx10^-3 J
rArr_L = 5 mJ

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#### APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 17 Alternating Current
Q 15 | Page 330
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