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Consider the Compounds, Bcl3 and Ccl4. How Will They Behave with Water? Justify. - Chemistry

Consider the compounds, BCland CCl4. How will they behave with water? Justify.

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Solution 1

Being a Lewis acid, BClreadily undergoes hydrolysis. Boric acid is formed as a result.

`BCl_3 + 3H_2O -> 3HCl + B(OH)_3`

CCl4 completely resists hydrolysis. Carbon does not have any vacant orbital. Hence, it cannot accept electrons from water to form an intermediate. When CCl4 and water are mixed, they form separate layers.

`CCl_4  + H_2O` -> No reaction

Solution 2

In BCl3, there is only six electrons in the valence shell of B atom. Thus, the octet is incomplete and it can accept a pair of electrons from water and hence BCl3 undergoes hydrolysis. Whereas, in CCl4, C atom has 8 electrons and its octet is complete. That’s why it has no tendency to react with water

CCl4 + H20 —————> No reaction

Concept: Important Trends and Anomalous Behaviour of Carbon
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NCERT Class 11 Chemistry Textbook
Chapter 11 The p-Block Elements
Q 4 | Page 323
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