#### Question

A gun of mass 3 kg fires a bullet of mass 30 g. The bullet takes 0.003 s to move through the barrel of the gun and acquires a velocity of 100 m/s. Calculate :

(i) the velocity with which the gin recoils.

(ii) the force exerted on gunman due to recoil of the gun

#### Solution

Mass of bullet, m = 30 g

= `30/1000` kg

= 0.03 kg

Velocity of bullet, v = 100 m/s

Mass of gun, M = 3 kg

Recoil velocity of gun , `V = -(0.03 xx 100)/3`

⇒ V = `-3/3`

⇒ V = -1 m/s

Is there an error in this question or solution?

Solution A Gun of Mass 3 Kg Fires a Bullet of Mass 30 G. the Bullet Takes 0.003 S to Move Through the Barrel of the Gun and Acquires a Velocity of 100 M/S. Calculate Concept: Conservation of Momentum.