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A Gun of Mass 3 Kg Fires a Bullet of Mass 30 G. the Bullet Takes 0.003 S to Move Through the Barrel of the Gun and Acquires a Velocity of 100 M/S. Calculate - CBSE Class 9 - Science

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Question

A gun of mass 3 kg fires a bullet of mass 30 g. The bullet takes 0.003 s to move through the barrel of the gun and acquires a velocity of 100 m/s. Calculate :

(i) the velocity with which the gin recoils.
(ii) the force exerted on gunman due to recoil of the gun

Solution

Mass of bullet, m = 30 g
= `30/1000` kg
= 0.03 kg
Velocity of bullet, v = 100 m/s
Mass of gun, M = 3 kg
Recoil velocity of gun , `V = -(0.03 xx 100)/3`
⇒ V = `-3/3`
⇒ V = -1 m/s

  Is there an error in this question or solution?

APPEARS IN

 Lakhmir Singh Solution for Science for Class 9 Part 1 Physics (2016 to Current)
Chapter 2: Force and Laws of Motion
Short Answers | Q: 33 | Page no. 75

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Solution A Gun of Mass 3 Kg Fires a Bullet of Mass 30 G. the Bullet Takes 0.003 S to Move Through the Barrel of the Gun and Acquires a Velocity of 100 M/S. Calculate Concept: Conservation of Momentum.
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