HSC Science (Electronics) 12th Board ExamMaharashtra State Board
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# Solution for The equation of tangent to the curve y=y=x^2+4x+1 at - HSC Science (Electronics) 12th Board Exam - Mathematics and Statistics

ConceptConics Tangents and normals - equations of tangent and normal at a point

#### Question

The equation of tangent to the curve y=y=x^2+4x+1 at

(-1,-2) is...............

(a)  2x -y = 0                        (b)  2x+y-5 = 0

(c)  2x-y-1=0                        (d)  x+y-1=0

#### Solution

(a)

y=x^2+4x+1

Differentiating w.r.t 'x', we get

dy/dx=2x+4

dy/dx|_(x->-1) =2(-1)+4=2

Hence, slope of tangent at (-1, -2) is 2.
So equation of tangent line is

y -(-2)= 2( x-(- 1))
2x - y = 0

Is there an error in this question or solution?

#### APPEARS IN

2015-2016 (March) (with solutions)
Question 4.1.2 | 2.00 marks

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Solution for question: The equation of tangent to the curve y=y=x^2+4x+1 at concept: Conics - Tangents and normals - equations of tangent and normal at a point. For the courses HSC Science (Electronics), HSC Arts, HSC Science (General) , HSC Science (Computer Science)
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