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Solution - The equation of tangent to the curve y=y=x^2+4x+1 at - Conics - Tangents and normals - equations of tangent and normal at a point

Question

The equation of tangent to the curve y=`y=x^2+4x+1` at

(-1,-2) is...............

(a)  2x -y = 0                        (b)  2x+y-5 = 0

(c)  2x-y-1=0                        (d)  x+y-1=0

Solution

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APPEARS IN

2015-2016 (March)
Question 4.1.2 | 2 marks
Solution for question: The equation of tangent to the curve y=y=x^2+4x+1 at concept: Conics - Tangents and normals - equations of tangent and normal at a point. For the courses HSC Arts, HSC Science (Computer Science), HSC Science (Electronics), HSC Science (General)
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