HSC Science (Computer Science) 12th Board ExamMaharashtra State Board
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Resistance of Conductivity Cell Filled with 0.1 M Kcl Solution is 100 Ohms. If the Resistance of the Same Cell When Filled with 0.02 M Kcl Solution is 520 Ohms, Calculate the Conductivity and Molar Conductivity of 0.02 M Kcl Solution. - HSC Science (Computer Science) 12th Board Exam - Chemistry

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Question

Resistance of conductivity cell filled with 0.1 M KCl solution is 100 ohms. If the resistance of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. [Given: Conductivity of 0.1 M KCl solution is 1.29 S m-1 .]

Solution

Given: For 0.1 M KCl, k = 1.29 S m-1 = 0.0129 S cm-1, R = 100 ohms or 0.02 M KCl, R = 520 ohms

To find: Conductivity and molar conductivity of 0.02 M KCl solution.

Formulae: a. Cell constant, b = k x R

b. Conductivity, k(KCl, 0.02 M) = Cellconstant /Resistance

c.Molar conductivity = 1000 k/C

Calculation: From formula (a),
b = k x R
= 0.0129 x 100 = 1.29 cm-1

From formula (b),
Conductivity, k(KCl, 0.02 M) = Cellconstant/Resistance

= 1.29/520
= 2.48 x 10-3 ohm-1 cm-1

From formula (c),
Molar conductivity of 0.02 M KCl solution = 1000k/C

=(1000 x 2.48 x 10 -3)/0.02

=124 ohm-1 cm2 mol-1

 

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APPEARS IN

 2014-2015 (October) (with solutions)
Question 3.3 | 3.00 marks
Solution Resistance of Conductivity Cell Filled with 0.1 M Kcl Solution is 100 Ohms. If the Resistance of the Same Cell When Filled with 0.02 M Kcl Solution is 520 Ohms, Calculate the Conductivity and Molar Conductivity of 0.02 M Kcl Solution. Concept: Conductance of Electrolytic Solutions - Variation of Conductivity and Molar Conductivity with Concentration.
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