HSC Science (General) 12th Board ExamMaharashtra State Board
Share

Conductivity of a solution is 6.23 x 10-5  Ω-1cm-1 and its resistance is 13710Ω. If the electrodes are 0.7cm apart, calculate the cross-sectional area of electrode - HSC Science (General) 12th Board Exam - Chemistry

ConceptConductance of Electrolytic Solutions - Introduction

Question

Conductivity of a solution is 6.23 x 10-5  Ω-1cm-1 and its resistance is 13710Ω. If the electrodes are 0.7cm apart, calculate the cross-sectional area of electrode.

Solution

ross-sectional area of electrode:

k=1/R*l/a

a=1/R*l/k

a=1/13710*0.7/(6.23*10^-5)

a=0.82cm^2

Is there an error in this question or solution?

APPEARS IN

2015-2016 (March) (with solutions)
Question 3.1.3 | 3.00 marks

Video TutorialsVIEW ALL 

Solution Conductivity of a solution is 6.23 x 10-5  Ω-1cm-1 and its resistance is 13710Ω. If the electrodes are 0.7cm apart, calculate the cross-sectional area of electrode Concept: Conductance of Electrolytic Solutions - Introduction.
S