HSC Science (General) 12th Board ExamMaharashtra State Board
Account
It's free!

User


Login
Create free account


      Forgot password?
Share
Notifications

View all notifications
Books Shortlist
Your shortlist is empty

Solution - Conductivity of a solution is 6.23 x 10-5  Ω-1cm-1 and its resistance is 13710Ω. If the electrodes are 0.7cm apart, calculate the cross-sectional area of electrode - HSC Science (General) 12th Board Exam - Chemistry

Question

Conductivity of a solution is 6.23 x 10-5  Ω-1cm-1 and its resistance is 13710Ω. If the electrodes are 0.7cm apart, calculate the cross-sectional area of electrode.

Solution

ross-sectional area of electrode:

`k=1/R*l/a`

`a=1/R*l/k`

`a=1/13710*0.7/(6.23*10^-5)`

`a=0.82cm^2`

 

Is there an error in this question or solution?

APPEARS IN

 2015-2016 (March) (with solutions)
Question 3.1.3 | 3 marks

Related QuestionsVIEW ALL [1]

Video TutorialsVIEW ALL [1]

Reference Material

Solution for question: Conductivity of a solution is 6.23 x 10-5  Ω-1cm-1 and its resistance is 13710Ω. If the electrodes are 0.7cm apart, calculate the cross-sectional area of electrode concept: Conductance of Electrolytic Solutions - Introduction. For the courses HSC Science (General) , HSC Science (Computer Science), HSC Science (Electronics)
S