#### Question

A fair coin is tossed five times. Find the probability that it shows exactly three times head.

#### Solution

Let X be the radom variable.

let 'p' be the success and 'q' be the failure

p=1/2, q=1/2

p(Coin shows 3 heads)

=p(x=3)=5c_{3}p^{3}q^{2}

= 10 (1/2)^{3}(1/2)^{2}

=10/32

=5/16

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#### APPEARS IN

Solution A Fair Coin is Tossed Five Times. Find the Probability that It Shows Exactly Three Times Head. Concept: Conditional Probability.