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A Fixed Pulley is Driven by a 100 Kg Mass Falling at a Rate of 8.0 M in 4.0s. It Lifts a Load of 500 Kgf. (A) Calculate the Power Input to the Pulley Taking the Force of Gravity on 1 Kg as 10 N. (B) I - ICSE Class 10 - Physics

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Question

A fixed pulley is driven by a 100 kg mass falling at a rate of 8.0 m in 4.0s. It lifts a load of 500 kgf.
(a) Calculate the power input to the pulley taking the force of gravity on 1 kg as 10 N.
(b) If the efficiency of the pulley is 75%, find the height to which the load is raised in 4.0s.

Solution

Load = 500 kgf
Mass of falling object = 100 kg
Displacement of effort = 8.0 m
Time taken = 4.0s
(a) Effort = 100 X 10 = 1000 kgf
Power Input = `"π‘‘π‘–π‘ π‘π‘™π‘Žπ‘π‘’π‘šπ‘’π‘›π‘‘ ×π‘’π‘“π‘“π‘œπ‘Ÿπ‘‘ "/"π‘‘π‘–π‘šπ‘’"` = `8 ×1000/4` = 2000 W
(b) The efficiency of the pulley is = 75% = 0.75

Mechanical advantage of this system M.A =`" πΏπ‘œπ‘Žπ‘‘"/"πΈπ‘“π‘“π‘œπ‘Ÿπ‘‘"`=`500/100` =5 Velocity ratio of this system V.R = `"𝑀.𝐴"/"πœ‚"`= `5/0.75`= `20/3`
Displacement of load D= `"π‘‘π‘–π‘ π‘π‘™π‘Žπ‘π‘’π‘šπ‘’π‘›π‘‘ π‘œπ‘“ π‘’π‘“π‘“π‘œπ‘Ÿπ‘‘"/"𝑉.𝑅"`= `(3×8)/20` = 1.2π‘š

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Solution A Fixed Pulley is Driven by a 100 Kg Mass Falling at a Rate of 8.0 M in 4.0s. It Lifts a Load of 500 Kgf. (A) Calculate the Power Input to the Pulley Taking the Force of Gravity on 1 Kg as 10 N. (B) I Concept: Concept of Pulley System.
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