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# Solution for A 4 M Long Rod of Negligible Weight is to Be Balanced About a Point 125 Cm from One End. a Load of 18 Kgf is Suspended at a Point 60 Cm from the Support on the Shorter Arm. - ICSE Class 10 - Physics

#### Question

A 4 m long rod of negligible weight is to be balanced about a point 125 cm from one end. A load of 18 kgf is suspended at a point 60 cm from the support on the shorter arm.
(a) a weight W is placed 250 cm from the support on the longer arm Find W.
(b) If W = 5 kgf, where must it be kept to balance the rod?
(c) To which class of lever does it belong?

#### Solution

Total length of rod=4 m = 400 cm
(a) 18kgf load is placed at 60 cm from the support.
W kgf weight is placed at 250 cm from the support.
By the principle of moments
18 x 60 = W x 250
W = 4.32 kgf
(b) Given W=5 kgf
18kgf load is placed at 60 cm from the support.
Let 5 kgf of weight is placed at d cm from the support.
By the principle of moments
18 x 60 = 5 x d
d = 216 cm from the support on the longer arm
(c) It belongs to class I lever.

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#### APPEARS IN

Solution A 4 M Long Rod of Negligible Weight is to Be Balanced About a Point 125 Cm from One End. a Load of 18 Kgf is Suspended at a Point 60 Cm from the Support on the Shorter Arm. Concept: Concept of Lever.
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