#### Question

Show that `(4/3 m - 3/4 n)^2 + 2mn = 16/9 m^2 + 9/16 n^2`

#### Solution

L.H.S = `(4/3 m - 3/4n)^2 + 2mn`

= `(4/3 m)^2 - 2(4/3 m)(3/4 n) + (3/4 n)^2 + 2mn`

= `16/9 m^2 - 2mn + 9/16 n^2 + 2mn`

= `16/9 m^2 + 9/16 n^2` = R.H.S

Is there an error in this question or solution?

Solution Show that (4by3 M - 3by4 N)Square2 + 2mn = 16/9 Msquare2 + 9by16 Nsquare2 Concept: Concept of Identity.